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22 articles found matching your search request ‘midrange’…

• Function Design: New 3-6 Output Functions

  …    // evaluate min(x0,x1), max(x0,x1) and midrange     double min = x[0];    double max = x[1];     …      min = x[1];        max = x[0];    }    double midrange = (max + min)/2.0;        double output = 0.0;     … = 0.0;    if (x[2] >= min && x[2] < midrange)        output = 1.0;    if (x[2] >= midrange …

  Posted Dec 11, 11:47 PM, Author Dr. Candida Ferreira

• Function Design: 5-Output Mapper Functions

  …min(x,y,z), max(x,y,z), midleValue(x,y,z), midrange1, midrange2     //     // evaluate min(x,y,z)      … argmax)        midleValue = x[1];    // evaluate midrange1 and midrange2     double midrange1 = (min + … midleValue)/2.0;    double midrange2 = (midleValue + max)/2.0;     double output = …     else if (x[3] >= min && x[3] < midrange1)        output = 1.0;    else if (x[3] >= … midrange1 && x[3] < midrange2)        output = 2.0;    else if (x[3] >= …

  Posted Dec 18, 09:51 PM, Author Dr. Candida Ferreira

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